Given the following IPv6 address 2340:0000:0010:0100:1000:ABCD:0101:1010. Which of the following is the the abbreviated form?

(A) 2340:0:10:100:1:ABCD:11:1010
(B) 2340:0:10:100:1:ABCD:101:11
(C) 234:0:10:100:1:ABCD:101:1010
(D) 2340:0:10:100:1:ABCD:101:1010

2340:0:10:100:1:ABCD:101:1010 is the correct answer. To abbreviate IPv6 addresses, only leading 0s in a quartet (one set of four hex digits) should be removed. Many of the quartets have trailing 0s (0s on the right side of the quartet), so make sure to not remove those 0s.

The unabbreviated version of an IPv6 address must have 32 digits. The :: was replaced with four quartets of 0000, making the number have eight sets of hex digits total (32 digits). Also, for each quartet with fewer than four digits, leading 0s were added so that each quartet has four hex digits.