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The broadcast address from the IP address 67.68.67.68/12 is 67.79.255.255.
(A) TRUE
(B) FALSE
TRUE is the correct answer. First, you have to find the subnet mask for the prefix /12. The prefix length means that the subnet mask in binary is: 11111111.11110000.00000000.00000000
Now, convert the subnet mask from binary to decimal. The subnet mask in decimal is 255.240.0.0, so the network ID multiplier is 256 – 240 = 16
Possible subnet IDs are:
67.0.0.0
67.16.0.0
67.32.0.0
67.48.0.0
67.64.0.0
67.80.0.0
etc etc
The network 67.64.0.0 has the IP address of 67.68.67.68
The IP address range of the network is 67.64.0.0 – 67.79.255.255 (the next address 67.80.0.0 is the next subnet ID)
The broadcast address is the last address of the network so, the broadcast address is 67.79.255.255
Now, convert the subnet mask from binary to decimal. The subnet mask in decimal is 255.240.0.0, so the network ID multiplier is 256 – 240 = 16
Possible subnet IDs are:
67.0.0.0
67.16.0.0
67.32.0.0
67.48.0.0
67.64.0.0
67.80.0.0
etc etc
The network 67.64.0.0 has the IP address of 67.68.67.68
The IP address range of the network is 67.64.0.0 – 67.79.255.255 (the next address 67.80.0.0 is the next subnet ID)
The broadcast address is the last address of the network so, the broadcast address is 67.79.255.255
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