The senior network engineer asked you to choose the broadcast address from the last subnet according to the following details:

Network 172.28.0.0 (Class B)
Mask 255.255.0.0 (for all subnets)

(A) 172.28.255.254
(B) 172.255.255.255
(C) 172.28.200.255
(D) 172.28.255.255

172.28.255.255 is the correct answer.

First subnet
Subnet Network: 172.28.0.0
IP Addresses: 172.28.0.1 – 172.28.0.254
Broadcast Address: 172.28.0.255

Second subnet
Subnet Network: 172.28.1.0
IP Addresses: 172.28.1.1 – 172.28.1.254
Broadcast Address: 172.28.1.255

Third subnet
Subnet Network: 172.28.3.0
IP Addresses: 172.28.3.1 – 172.28.3.254
Broadcast Address: 172.28.3.255

etc etc…

Last subnet
Subnet Network: 172.28.255.0
IP Addresses: 172.28.255.1 – 172.28.255.254
Broadcast Address: 172.28.255.255