Which of the following addresses is the unabbreviated version of IPv6 address 8002:AA3::100:30?

(A) 8002:0AA3:0000:0000:0000:0000:0100:0030
(B) 8002:0DAA3::0100:0030
(C) 8002:0AA3:0:0:0:0:0100:0030
(D) 82:AA3:0:0:0:0:1:3

8002:0AA3:0000:0000:0000:0000:0100:0030 is the correct answer. The unabbreviated version of an IPv6 address must have 32 digits, and only one answer has 32 hex digits. In this case, the original number shows four quartets (sets of four hex digits) and a ::. So, the :: was replaced with four quartets of 0000, making the number have eight quartets. Then, for each quartet with fewer than four digits, leading 0s were added so that each quartet has four hex digits.